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All Numbers Are Equal
8 X5 K" c' y( p0 e6 ETheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then ' Y J# D( l2 x1 M9 s& A7 p
- ?/ \! t% ?9 _+ C: ca + b = t, p9 t! Z$ \, s2 x# d
(a + b)(a - b) = t(a - b)
( X1 S' N$ r, U% Sa^2 - b^2 = ta - tb
% Z% \, p' ?: Da^2 - ta = b^2 - tb' Y9 t) W. M$ l! m9 h* A7 X
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
; ]2 b5 D J2 z- C6 W+ g0 |$ f(a - t/2)^2 = (b - t/2)^2
) Z/ b( f9 R8 t, d- j4 Sa - t/2 = b - t/2 L' f. _8 Y# }
a = b 6 ?. O6 e: h# S; O% P% m
8 L- I( g, ?! ?: J: o
So all numbers are the same, and math is pointless. |
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