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[其他] 求助一到地球物理的题

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发表于 2012-4-2 21:27 | 显示全部楼层 |阅读模式
知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
8 y' ]( \7 _" G* A2 @
) X" p6 l, X+ c9 ]0 j3 p2 x" X3 J/ ^2 U2 i, d8 ]

5 p0 C3 [& W; H7 C(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:
" x- [9 j8 T/ i+ y' e8 R6 }9 \0 G% U2 f' W5 V; A" O$ a' c$ ~* f7 o
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.5 q3 _; t7 x# [  A& K) V' _5 P
7 M' a0 @; C  F% ]7 G( t- _& s; I
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).
8 k+ a5 J& E0 g( B. C: z) A
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