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[其他] 求助一到地球物理的题

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发表于 2012-4-2 21:27 | 显示全部楼层 |阅读模式
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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
0 m% `% q( k& [5 B2 E9 r7 r2 |! g0 N: n5 m' L
: c2 Y5 h1 O8 B% g; p2 u
. ~4 ^$ D$ B; ^; S* F+ I
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:0 v. x* G+ U" U5 k* r# C
  |7 c8 n; x) A, ^
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
- g$ N) m9 J* Q' e+ ~. q* A2 E. o: g, D: X& X, `" y+ [3 Q1 M7 q
Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).
9 N  f3 K9 Y/ l" t$ \) ~
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