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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 5 o& Z' n, a% t* x4 R! c
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$ d& i" V! S8 T6 \" r1 ^1 }) h足球看完了来看看题目。
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$ x4 ~) y; X4 | F* G" P) Q7 KThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
3 Y' e( v" g& d6 F; zThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different); C+ C, U( U, o) W q# D& b; M
We can see it is not easy to install the 22 meters heat trace according as figure 11 }; Y2 x! f$ Q ]0 d3 u
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: k0 O( `1 x0 b' ~( o6 r" O% dAs a normal question we just discuss:
8 q, F$ I/ l7 w2 @$ ]1 NHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? ! ~3 B2 Y4 F. i/ t
I call this is JACK LAI Spiral Method 螺旋法
, I* A$ ]2 Y0 Y0 X! p- w% JThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.! ~' L& K' R a! M
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. ' a" L+ x& F6 }% f3 D: G$ @
Because the pipe is horizontal, position 0 can not be placed. See figure 2
6 S( Z9 t8 K# h4 ]; B! r) {9 C, [Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
/ U) B* u" p/ s: N5 \The total heat trace that can be installed here is about
5 A$ t0 N6 c5 {1 d1 ^1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
0 c0 G( D( q6 w4 T0 ESo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :
. d% v5 I& b1 v% ^9 c! x1. The minimum bend radius:& d4 Y# P4 Q3 y. ]! c5 R1 B$ H
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
1 n, e5 \1 M2 h7 @6 ~; a* C5/16 *6 = 30/16 almost = 2 inches9 f0 G( Y ?' S& G. x3 Q
So the maximum bend radius is 2 inches.& V( _" P D' S/ ^- O. X1 \
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Summary% _. \' S! |) z# P
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
/ a+ B9 y7 t; J3 n+ n' h2 S" [ Zif the pipe is horizontal, The length of heat trace can be installed is about
$ c; k! u+ S' c; r. H. D1 * 9 = 9 meters
+ L. y; X8 f. e+ R a, kIf the pipe is vertical, The length of heat trace can be installed is about
2 P3 p1 R$ q& T) V9 q1 * 10 = 10 meters. ; c4 E% V9 ~7 o$ e
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
, S* H0 n1 O8 I2 d* vif the pipe is horizontal , The length of heat trace can be installed is about
/ K) [% N* n( p) S" g$ C: g1 * 4 = 4 meters
8 f) _$ U3 M0 D; |1 e9 u( s* uIf the pipe is vertical, The length of heat trace can be installed is about
9 d) {9 d" E1 @% P( W1 * 5 = 5 meters. |
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