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All Numbers Are Equal
& D1 p# t7 P6 _& `Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then ' N! u0 Y5 z7 F+ p
, O2 h, j0 D, X3 t) Za + b = t
9 D; E- C0 n" {. J! g$ K1 \* r(a + b)(a - b) = t(a - b)
3 b/ V1 Y/ j: }/ O+ D+ @- Y4 Qa^2 - b^2 = ta - tb
- y0 {" \- H. m2 ]% Ia^2 - ta = b^2 - tb# V. Y U3 N; @+ e" [% g% N% T2 T/ m$ N
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
5 S9 o- \" ~/ c+ t(a - t/2)^2 = (b - t/2)^2' ?6 D( @0 X! x* [% i
a - t/2 = b - t/2; i& r) ^* e7 ?8 e
a = b
1 f7 X" U ~! b* Y9 ~2 T
D4 T' M, a: q" F' T& @So all numbers are the same, and math is pointless. |
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