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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 5 g+ C7 R) s, i) t
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足球看完了来看看题目。
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& Q9 ]7 l6 c" d4 S7 n# h& \* EThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)' L: u" E& j' P+ Y: m- ]9 ^
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
: \# V/ ]" h+ N6 r6 u2 U; O1 }0 IWe can see it is not easy to install the 22 meters heat trace according as figure 1( _' z1 j: H+ h* s( C4 P& o& Z
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As a normal question we just discuss:
: ~! W5 ^" _/ L# m sHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
+ c N* \) H+ J. {3 g8 c* w: ZI call this is JACK LAI Spiral Method 螺旋法% d9 Z) W6 Z: i! _; w
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
7 a0 r4 g, j( T) P$ NThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. ; a1 u0 ?7 _0 E; g
Because the pipe is horizontal, position 0 can not be placed. See figure 2
- X; g9 H2 t+ `9 DBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 33 Q! [7 G) i' o* t$ S9 v+ I
The total heat trace that can be installed here is about * r$ c, r2 v' s+ t9 t' H, ]6 K
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters5 s2 B- k; k& W6 ]) S' f9 U# X
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :& \4 ?* t$ C" Q* r/ R/ Z6 h& g
1. The minimum bend radius:" M3 l j9 Y" I; @4 D: _
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
' D$ j5 i7 t# B5/16 *6 = 30/16 almost = 2 inches
, v; N, {+ ~0 J5 `" B9 l8 f6 ~So the maximum bend radius is 2 inches.
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Summary7 N/ o! R( k1 j9 K: X' @
As regular
1 s" @" {; F6 {& U2 EFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
* H- B7 j( ~* y+ b) n# q8 w$ L* l5 Hif the pipe is horizontal, The length of heat trace can be installed is about
9 Z0 V% x' q6 ^# v2 y* u# H. h1 * 9 = 9 meters
1 y7 F$ W+ z8 bIf the pipe is vertical, The length of heat trace can be installed is about
' f* P- g7 d' n4 Y) X8 L0 j1 * 10 = 10 meters.
- V2 w& F/ B* iFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
3 `+ W" C# d9 O6 Vif the pipe is horizontal , The length of heat trace can be installed is about
/ R' q/ g; a. l1 * 4 = 4 meters
; C6 U3 F! D" N/ N2 eIf the pipe is vertical, The length of heat trace can be installed is about0 @1 \1 M/ i; G; j; @- D4 E
1 * 5 = 5 meters. |
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