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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 5 z- B8 K% A+ t" z3 A. W* `
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5 O+ a- `( K q% w/ d6 s足球看完了来看看题目。
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)9 n4 v( H" o; r6 k/ W. t; r0 a
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)& W! {: {! E! k7 M! y& {8 l6 H! V% V
We can see it is not easy to install the 22 meters heat trace according as figure 15 v9 Z/ A( X1 F1 c) |/ V7 f/ k
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As a normal question we just discuss:
8 |" R% i" u2 |: q' }$ n! l4 GHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
) j! g4 W2 q+ ^, P6 t/ nI call this is JACK LAI Spiral Method 螺旋法
& t+ @' Q9 G; x! zThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.8 z m3 |: ^: D9 F+ m Q
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
5 b2 X2 ?# K9 G1 xBecause the pipe is horizontal, position 0 can not be placed. See figure 2- ~/ m$ w4 a5 s
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
# r7 F2 f& m6 [- I6 yThe total heat trace that can be installed here is about " d5 q) w+ i9 {7 {5 c; s) E
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
3 R0 y% t9 F% v5 ~- USo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 6 V$ l8 L G: r( C, _/ }6 p, i
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Note :& g+ @( _ A# c9 ]' p# U
1. The minimum bend radius:( ?% B T, ~& d* i' j) M1 f. _" _
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is2 ~: ^7 ]% i/ P6 f
5/16 *6 = 30/16 almost = 2 inches
. D5 D [% u% x& G) dSo the maximum bend radius is 2 inches.& ?$ D0 A$ x( u" ~7 e) \# z
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0 G* j, |2 O- ?, X ?Summary
" q9 E7 m6 d8 l% AAs regular
- O- s; i/ ^5 n8 R( G% ZFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe! m' e! S1 y% K; z- h# \5 e, M& E
if the pipe is horizontal, The length of heat trace can be installed is about
! W0 X- j: d6 I, `% P$ J1 * 9 = 9 meters
% t7 @( V: \: D8 y) S3 Z, q/ aIf the pipe is vertical, The length of heat trace can be installed is about
) `5 {6 z: M7 o* `1 * 10 = 10 meters. 7 \! Q1 g9 l$ p& A7 t, c8 D
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe- q/ K: \1 X7 ~6 _ q/ z# F
if the pipe is horizontal , The length of heat trace can be installed is about D2 e( l8 q, P' e/ ~
1 * 4 = 4 meters
9 J- ]' V/ E9 u/ j$ [If the pipe is vertical, The length of heat trace can be installed is about
. T: M0 z& f& F( ]1 y1 * 5 = 5 meters. |
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